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Bug fix for vanilla standard key rules

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This commit is contained in:
aerinon
2020-10-23 15:25:49 -06:00
parent c0f6c3fd52
commit a1782e3edc
1 changed files with 3 additions and 2 deletions
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5
KeyDoorShuffle.py
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@@ -243,13 +243,14 @@ def analyze_dungeon(key_layout, world, player):
possible_smalls = count_unique_small_doors(key_counter, key_layout.flat_prop)
avail_bigs = exist_relevant_big_doors(key_counter, key_layout) or exist_big_chest(key_counter)
non_big_locs = count_locations_big_optional(key_counter.free_locations)
if not key_counter.big_key_opened:
big_avail = key_counter.big_key_opened or (key_layout.big_key_special and any(x for x in key_counter.other_locations.keys() if x.forced_item and x.forced_item.bigkey))
if not big_avail:
if chest_keys == non_big_locs and chest_keys > 0 and available <= possible_smalls and not avail_bigs:
key_logic.bk_restricted.update(filter_big_chest(key_counter.free_locations))
# try to relax the rules here? - smallest requirement that doesn't force a softlock
child_queue = deque()
for child in key_counter.child_doors.keys():
if not child.bigKey or not key_layout.big_key_special or key_counter.big_key_opened:
if not child.bigKey or not key_layout.big_key_special or big_avail:
odd_counter = create_odd_key_counter(child, key_counter, key_layout, world, player)
empty_flag = empty_counter(odd_counter)
child_queue.append((child, odd_counter, empty_flag))