219 lines
4.4 KiB
C
219 lines
4.4 KiB
C
/* NetHack 3.7 rect.c $NHDT-Date: 1596498203 2020/08/03 23:43:23 $ $NHDT-Branch: NetHack-3.7 $:$NHDT-Revision: 1.14 $ */
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/* Copyright (c) 1990 by Jean-Christophe Collet */
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/* NetHack may be freely redistributed. See license for details. */
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#include "hack.h"
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int get_rect_ind(NhRect *);
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staticfn boolean intersect(NhRect *, NhRect *, NhRect *);
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/*
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* In this file, we will handle the various rectangle functions we
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* need for room generation.
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*/
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#define XLIM 4
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#define YLIM 3
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static NhRect *rect = (NhRect *) 0;
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static int n_rects = 0;
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static int rect_cnt;
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/*
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* Initialization of internal structures. Should be called for every
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* new level to be build...
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*/
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void
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init_rect(void)
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{
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if (!rect) {
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n_rects = (COLNO * ROWNO) / 30;
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rect = (NhRect *) alloc(sizeof(NhRect) * n_rects);
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if (!rect)
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panic("Could not alloc rect");
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}
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rect_cnt = 1;
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rect[0].lx = rect[0].ly = 0;
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rect[0].hx = COLNO - 1;
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rect[0].hy = ROWNO - 1;
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}
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void
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free_rect(void)
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{
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if (rect)
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free(rect);
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n_rects = rect_cnt = 0;
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}
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/*
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* Search Index of one precise NhRect.
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*
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*/
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int
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get_rect_ind(NhRect *r)
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{
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NhRect *rectp;
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int lx, ly, hx, hy;
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int i;
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lx = r->lx;
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ly = r->ly;
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hx = r->hx;
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hy = r->hy;
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for (i = 0, rectp = &rect[0]; i < rect_cnt; i++, rectp++)
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if (lx == rectp->lx && ly == rectp->ly && hx == rectp->hx
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&& hy == rectp->hy)
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return i;
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return -1;
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}
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/*
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* Search a free rectangle that include the one given in arg
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*/
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NhRect *
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get_rect(NhRect *r)
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{
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NhRect *rectp;
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int lx, ly, hx, hy;
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int i;
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lx = r->lx;
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ly = r->ly;
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hx = r->hx;
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hy = r->hy;
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for (i = 0, rectp = &rect[0]; i < rect_cnt; i++, rectp++)
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if (lx >= rectp->lx && ly >= rectp->ly && hx <= rectp->hx
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&& hy <= rectp->hy)
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return rectp;
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return 0;
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}
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/*
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* Get some random NhRect from the list.
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*/
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NhRect *
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rnd_rect(void)
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{
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return rect_cnt > 0 ? &rect[rn2(rect_cnt)] : 0;
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}
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/*
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* Search intersection between two rectangles (r1 & r2).
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* return TRUE if intersection exist and put it in r3.
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* otherwise returns FALSE
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*/
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staticfn boolean
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intersect(NhRect *r1, NhRect *r2, NhRect *r3)
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{
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if (r2->lx > r1->hx || r2->ly > r1->hy || r2->hx < r1->lx
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|| r2->hy < r1->ly)
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return FALSE;
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r3->lx = (r2->lx > r1->lx ? r2->lx : r1->lx);
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r3->ly = (r2->ly > r1->ly ? r2->ly : r1->ly);
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r3->hx = (r2->hx > r1->hx ? r1->hx : r2->hx);
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r3->hy = (r2->hy > r1->hy ? r1->hy : r2->hy);
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if (r3->lx > r3->hx || r3->ly > r3->hy)
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return FALSE;
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return TRUE;
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}
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/* Put the rectangle containing both r1 and r2 into r3 */
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void
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rect_bounds(NhRect r1, NhRect r2, NhRect *r3)
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{
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r3->lx = min(r1.lx, r2.lx);
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r3->ly = min(r1.ly, r2.ly);
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r3->hx = max(r1.hx, r2.hx);
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r3->hy = max(r1.hy, r2.hy);
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}
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/*
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* Remove a rectangle from the list of free NhRect.
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*/
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void
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remove_rect(NhRect *r)
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{
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int ind;
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ind = get_rect_ind(r);
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if (ind >= 0)
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rect[ind] = rect[--rect_cnt];
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}
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/*
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* Add a NhRect to the list.
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*/
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void
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add_rect(NhRect *r)
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{
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if (rect_cnt >= n_rects) {
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impossible("n_rects may be too small.");
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return;
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}
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/* Check that this NhRect is not included in another one */
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if (get_rect(r))
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return;
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rect[rect_cnt] = *r;
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rect_cnt++;
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}
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/*
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* Okay, here we have two rectangles (r1 & r2).
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* r1 was already in the list and r2 is included in r1.
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* What we want is to allocate r2, that is split r1 into smaller rectangles
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* then remove it.
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*/
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void
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split_rects(NhRect *r1, NhRect *r2)
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{
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NhRect r, old_r;
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int i;
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old_r = *r1;
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remove_rect(r1);
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/* Walk down since rect_cnt & rect[] will change... */
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for (i = rect_cnt - 1; i >= 0; i--)
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if (intersect(&rect[i], r2, &r))
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split_rects(&rect[i], &r);
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if (r2->ly - old_r.ly - 1
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> (old_r.hy < ROWNO - 1 ? 2 * YLIM : YLIM + 1) + 4) {
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r = old_r;
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r.hy = r2->ly - 2;
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add_rect(&r);
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}
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if (r2->lx - old_r.lx - 1
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> (old_r.hx < COLNO - 1 ? 2 * XLIM : XLIM + 1) + 4) {
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r = old_r;
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r.hx = r2->lx - 2;
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add_rect(&r);
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}
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if (old_r.hy - r2->hy - 1 > (old_r.ly > 0 ? 2 * YLIM : YLIM + 1) + 4) {
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r = old_r;
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r.ly = r2->hy + 2;
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add_rect(&r);
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}
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if (old_r.hx - r2->hx - 1 > (old_r.lx > 0 ? 2 * XLIM : XLIM + 1) + 4) {
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r = old_r;
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r.lx = r2->hx + 2;
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add_rect(&r);
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}
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}
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/*rect.c*/
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