Files
nethack/win/Qt4/qt4clust.cpp
Pasi Kallinen ed335dd0a7 Add Qt4 windowport
Originally by Ray Chason for 3.4.3, based on the Qt windowport by
Warwick Allison. The look and feel is mostly the same.

Some improvements over the Qt 3 interface are:

* Panes are resizable
* Full support for IBMgraphics, and walls and corridors are drawn with
  graphical primitives for a continuous appearance no matter what the font
  says
* Lots of irritating glitches fixed
* Menus support proportional fonts correctly

Adding this because the old Qt windowport cannot be compiled on Qt4,
even with Qt3 compatibility stuff.

TODO:
 - background map glyphs
 - status hilites
 - menucolors
2017-10-08 01:15:02 +03:00

168 lines
3.6 KiB
C++

/* SCCS Id: @(#)qt_clust.cpp 3.4 1999/11/19 */
/* Copyright (c) Warwick Allison, 1999. */
/* NetHack may be freely redistributed. See license for details. */
#include "qt4clust.h"
static void include(QRect& r, const QRect& rect)
{
if (rect.left()<r.left()) {
r.setLeft(rect.left());
}
if (rect.right()>r.right()) {
r.setRight(rect.right());
}
if (rect.top()<r.top()) {
r.setTop(rect.top());
}
if (rect.bottom()>r.bottom()) {
r.setBottom(rect.bottom());
}
}
/*
A Clusterizer groups rectangles (QRects) into non-overlapping rectangles
by a merging heuristic.
*/
Clusterizer::Clusterizer(int maxclusters) :
cluster(new QRect[maxclusters]),
count(0),
max(maxclusters)
{ }
Clusterizer::~Clusterizer()
{
delete [] cluster;
}
void Clusterizer::clear()
{
count=0;
}
void Clusterizer::add(int x, int y)
{
add(QRect(x,y,1,1));
}
void Clusterizer::add(int x, int y, int w, int h)
{
add(QRect(x,y,w,h));
}
void Clusterizer::add(const QRect& rect)
{
QRect biggerrect(rect.x()-1,rect.y()-1,rect.width()+2,rect.height()+2);
//assert(rect.width()>0 && rect.height()>0);
int cursor;
for (cursor=0; cursor<count; cursor++) {
if (cluster[cursor].contains(rect)) {
// Wholly contained already.
return;
}
}
int lowestcost=9999999;
int cheapest=-1;
for (cursor=0; cursor<count; cursor++) {
if (cluster[cursor].intersects(biggerrect)) {
QRect larger=cluster[cursor];
include(larger,rect);
int cost=larger.width()*larger.height()
- cluster[cursor].width()*cluster[cursor].height();
if (cost < lowestcost) {
bool bad=false;
for (int c=0; c<count && !bad; c++) {
bad=cluster[c].intersects(larger) && c!=cursor;
}
if (!bad) {
cheapest=cursor;
lowestcost=cost;
}
}
}
}
if (cheapest>=0) {
include(cluster[cheapest],rect);
return;
}
if (count < max) {
cluster[count++]=rect;
return;
}
// Do cheapest of:
// add to closest cluster
// do cheapest cluster merge, add to new cluster
lowestcost=9999999;
cheapest=-1;
for (cursor=0; cursor<count; cursor++) {
QRect larger=cluster[cursor];
include(larger,rect);
int cost=larger.width()*larger.height()
- cluster[cursor].width()*cluster[cursor].height();
if (cost < lowestcost) {
bool bad=false;
for (int c=0; c<count && !bad; c++) {
bad=cluster[c].intersects(larger) && c!=cursor;
}
if (!bad) {
cheapest=cursor;
lowestcost=cost;
}
}
}
// XXX could make an heuristic guess as to whether we
// XXX need to bother looking for a cheap merge.
int cheapestmerge1=-1;
int cheapestmerge2=-1;
for (int merge1=0; merge1<count; merge1++) {
for (int merge2=0; merge2<count; merge2++) {
if (merge1!=merge2) {
QRect larger=cluster[merge1];
include(larger,cluster[merge2]);
int cost=larger.width()*larger.height()
- cluster[merge1].width()*cluster[merge1].height()
- cluster[merge2].width()*cluster[merge2].height();
if (cost < lowestcost) {
bool bad=false;
for (int c=0; c<count && !bad; c++) {
bad=cluster[c].intersects(larger) && c!=cursor;
}
if (!bad) {
cheapestmerge1=merge1;
cheapestmerge2=merge2;
lowestcost=cost;
}
}
}
}
}
if (cheapestmerge1>=0) {
include(cluster[cheapestmerge1],cluster[cheapestmerge2]);
cluster[cheapestmerge2]=cluster[count--];
} else {
// if (!cheapest) debugRectangles(rect);
include(cluster[cheapest],rect);
}
// NB: clusters do not intersect (or intersection will
// overwrite). This is a result of the above algorithm,
// given the assumption that (x,y) are ordered topleft
// to bottomright.
}
const QRect& Clusterizer::operator[](int i)
{
return cluster[i];
}