stabilize loss of gold

When gold is stolen by a leprechaun or lost when being "overwhelmed
by an urge to take a bath" while dipping in a fountain, if you had
99 gold pieces or less, you'd lose all of it (in the bath case, only
if it was at least 10 to start with), but if you had 100 or more,
you would lose a random amount which could be as little as 1.  And
in the bath case, if the random amount was less than 10, you would
lose nothing but be told that "you lost some of your money in the
fountain".  After this change, it is still possible to lose less
when starting with more, but not as likely and not as extreme a case
as maybe losing only 1 when starting with thousands.

The fountain-dip bath case has code to handle mutiple denominations
of coins, possibly the only place in the program where that exists.
I've left that alone although it should probably be taken out....
This commit is contained in:
PatR
2015-05-01 18:01:12 -07:00
parent d29ee35ae8
commit 274904f9be

View File

@@ -1,4 +1,4 @@
/* NetHack 3.5 steal.c $NHDT-Date$ $NHDT-Branch$:$NHDT-Revision$ */
/* NetHack 3.5 steal.c $NHDT-Date: 1430528463 2015/05/02 01:01:03 $ $NHDT-Branch: master $:$NHDT-Revision: 1.53 $ */
/* NetHack 3.5 steal.c $Date: 2012/02/05 04:26:48 $ $Revision: 1.41 $ */
/* Copyright (c) Stichting Mathematisch Centrum, Amsterdam, 1985. */
/* NetHack may be freely redistributed. See license for details. */
@@ -23,15 +23,31 @@ register struct obj *otmp;
}
long /* actually returns something that fits in an int */
somegold(umoney)
long umoney;
somegold(lmoney)
long lmoney;
{
#ifdef LINT /* long conv. ok */
return(0L);
int igold = 0;
#else
return (long)( (umoney < 100) ? umoney :
(umoney > 10000) ? rnd(10000) : rnd((int) umoney) );
int igold = (lmoney >= (long)LARGEST_INT) ? LARGEST_INT : (int)lmoney;
#endif
if (igold < 50)
; /* all gold */
else if (igold < 100)
igold = rn1(igold - 25 + 1, 25);
else if (igold < 500)
igold = rn1(igold - 50 + 1, 50);
else if (igold < 1000)
igold = rn1(igold - 100 + 1, 100);
else if (igold < 5000)
igold = rn1(igold - 500 + 1, 500);
else if (igold < 10000)
igold = rn1(igold - 1000 + 1, 1000);
else
igold = rn1(igold - 5000 + 1, 5000);
return (long)igold;
}
/*